F(-2)=2x^2-x+3

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Solution for F(-2)=2x^2-x+3 equation: 



(-2)=2F^2-F+3

We move all terms to the left:

(-2)-(2F^2-F+3)=0

We add all the numbers together, and all the variables

-(2F^2-F+3)-2=0

We get rid of parentheses

-2F^2+F-3-2=0

We add all the numbers together, and all the variables

-2F^2+F-5=0

a = -2; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·(-2)·(-5)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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